IGCSE MATH: VECTORS
Vectors in Two Dimensions: Complete Guide
E7.2 - Vectors in Two Dimensions
What is a Vector?
A vector is a quantity that has both:
- Magnitude (size/length)
- Direction (which way it points)
Examples: displacement, velocity, force
Vector Notation
Vectors can be written in several ways:
- Bold letters: a, AB
- Underlined: a̲, AB̲
- With arrow: AB→ (read as "vector AB")
- Column vector: (x/y) where x is horizontal, y is vertical
Example notations for the same vector:
- AB→
- a
- (3/4) - meaning 3 units right, 4 units up
1. Describing Translations Using Vectors
A vector describes how to move from one point to another:
- The top number tells you horizontal movement (x-direction)
- The bottom number tells you vertical movement (y-direction)
a = (x/y) means:
• Move x units horizontally (+ right, - left)
• Move y units vertically (+ up, - down)
Example 1: Reading a Vector
Vector: a = (5/3)
Meaning: Move 5 units right and 3 units up
Vector: b = (-2/4)
Meaning: Move 2 units left and 4 units up
Vector: c = (3/-5)
Meaning: Move 3 units right and 5 units down
2. Adding and Subtracting Vectors
(a/b) + (c/d) = (a+c / b+d)
Add corresponding components separately
(a/b) - (c/d) = (a-c / b-d)
Subtract corresponding components separately
Example 2: Vector Addition
Question: Find a + b where a = (3/2) and b = (1/4)
Solution:
- a + b = (3/2) + (1/4)
- = (3+1 / 2+4)
- = (4/6)
Answer: (4/6)
Meaning: Combined movement is 4 right, 6 up
Example 3: Vector Subtraction
Question: Find a - b where a = (5/3) and b = (2/1)
Solution:
- a - b = (5/3) - (2/1)
- = (5-2 / 3-1)
- = (3/2)
Answer: (3/2)
• a + b: Follow vector a, then follow vector b
• a - b: The vector from the end of b to the end of a
3. Multiplying a Vector by a Scalar
A scalar is just a number (not a vector)
Multiplying a vector by a scalar changes its magnitude but not its direction (unless negative)
k × (a/b) = (ka / kb)
Multiply each component by the scalar k
Example 4: Scalar Multiplication
Question: Find 3a where a = (2/-1)
Solution:
- 3a = 3 × (2/-1)
- = (3×2 / 3×(-1))
- = (6/-3)
Answer: (6/-3)
Meaning: Three times as long in the same direction
Example 5: Negative Scalar
Question: Find -2b where b = (3/4)
Solution:
- -2b = -2 × (3/4)
- = (-2×3 / -2×4)
- = (-6/-8)
Answer: (-6/-8)
Meaning: Twice as long in the OPPOSITE direction
- Multiplying by a positive number: same direction, different length
- Multiplying by a negative number: opposite direction
- Multiplying by 1: no change
- Multiplying by 0: gives zero vector (0/0)
E7.3 - Magnitude of a Vector
What is Magnitude?
The magnitude of a vector is its length or size
It's always a positive number (or zero)
Denoted by: |a| or |AB→|
For vector a = (x/y):
|a| = √(x² + y²)
This comes from Pythagoras' theorem!
Example 6: Finding Magnitude
Question: Find |a| where a = (3/4)
Solution:
- |a| = √(3² + 4²)
- = √(9 + 16)
- = √25
- = 5
Answer: 5 units
Example 7: Magnitude with Decimals
Question: Find |b| where b = (5/2)
Solution:
- |b| = √(5² + 2²)
- = √(25 + 4)
- = √29
- ≈ 5.39 units
Answer: √29 or 5.39 units (to 2 d.p.)
Example 8: Negative Components
Question: Find |c| where c = (-6/-8)
Solution:
- |c| = √((-6)² + (-8)²)
- = √(36 + 64)
- = √100
- = 10
Answer: 10 units
Note: Negative components become positive when squared!
E7.4 - Vector Geometry
1. Representing Vectors by Directed Line Segments
Vectors can be drawn as arrows on a grid:
- The length of the arrow represents magnitude
- The direction of the arrow shows direction
- The starting point can be anywhere (vectors are about movement, not position)
2. Position Vectors
A position vector describes the position of a point relative to the origin (0, 0)
If point A has coordinates (x, y), its position vector is OA→ = (x/y)
Example 9: Position Vectors
Question: Point A is at (3, 5). What is the position vector OA→?
Solution:
- Position vector from origin O(0,0) to A(3,5)
- OA→ = (3/5)
Answer: (3/5)
3. Expressing Vectors in Terms of Two Coplanar Vectors
Coplanar vectors lie in the same plane (2D space)
Any 2D vector can be expressed as a combination of two non-parallel vectors
These are called base vectors or component vectors
i = (1/0) → one unit right
j = (0/1) → one unit up
Any vector (a/b) = ai + bj
Example 10: Expressing in Terms of i and j
Question: Express v = (4/3) in terms of i and j
Solution:
- v = (4/3)
- = 4i + 3j
Answer: 4i + 3j
Example 11: Sum and Difference of Vectors
Question: In triangle ABC, AB→ = p and BC→ = q. Express AC→ in terms of p and q
Solution:
- To go from A to C, we can go A→B→C
- AC→ = AB→ + BC→
- AC→ = p + q
Answer: p + q
4. Using Vectors to Solve Geometric Problems
Applications Include:
- Showing vectors are parallel
- Showing points are collinear (lie on same line)
- Solving problems with ratio and similarity
Two vectors are parallel if one is a scalar multiple of the other
If a = kb (where k is a number), then a and b are parallel
Example 12: Showing Vectors are Parallel
Question: Show that a = (6/9) and b = (2/3) are parallel
Solution:
- Check if a = kb for some number k
- (6/9) = k(2/3)
- 6 = 2k → k = 3
- 9 = 3k → k = 3 ✓
- Since a = 3b, they are parallel
Answer: Vectors are parallel (a = 3b)
Three points A, B, C are collinear if AB→ and AC→ are parallel
This means AB→ = k × AC→ for some scalar k
Example 13: Showing Points are Collinear
Question: Points A, B, C have position vectors (1/2), (3/5), (5/8). Are they collinear?
Solution:
- Find AB→ = (3/5) - (1/2) = (2/3)
- Find AC→ = (5/8) - (1/2) = (4/6)
- Check if parallel: AC→ = (4/6) = 2(2/3) = 2 × AB→
- Since AC→ = 2AB→, the vectors are parallel
- They share point A, so A, B, C are collinear
Answer: Yes, points are collinear
Example 14: Ratio and Similarity
Question: Point M divides AB in ratio 2:3. If OA→ = a and OB→ = b, find OM→
Solution:
- M divides AB in ratio 2:3 means AM:MB = 2:3
- Total parts = 2 + 3 = 5
- M is 2/5 of the way from A to B
- OM→ = OA→ + (2/5)AB→
- AB→ = OB→ - OA→ = b - a
- OM→ = a + (2/5)(b - a)
- = a + (2/5)b - (2/5)a
- = (3/5)a + (2/5)b
Answer: OM→ = (3/5)a + (2/5)b
Common Mistakes to Avoid
- ❌ Confusing magnitude with direction
- ❌ Forgetting to square the components when finding magnitude
- ❌ Adding/subtracting x and y components together (keep separate!)
- ❌ Forgetting that magnitude is always positive
- ❌ Not checking if vectors are parallel when proving collinearity
- ❌ Mixing up position vectors with displacement vectors
Practice Problems
Vector Operations:
- If a = (3/4) and b = (2/-1), find:
- a) a + b
- b) a - b
- c) 2a + 3b
Magnitude:
- Find the magnitude of:
- a) (5/12)
- b) (-3/4)
- c) (7/-24)
Parallel Vectors:
- Are vectors (4/6) and (6/9) parallel? Show your working.
Collinearity:
- Points P, Q, R have position vectors (2/3), (5/7), (8/11). Are they collinear?
Answers:
- a) (5/3) b) (1/5) c) (12/5)
- a) 13 b) 5 c) 25
- Yes, (6/9) = 1.5 × (4/6), so they are parallel
- Yes, PQ→ = (3/4) and PR→ = (6/8) = 2(3/4), so collinear
Quick Reference Summary
| Operation | Formula | Example |
|---|---|---|
| Addition | (a/b) + (c/d) = (a+c / b+d) | (2/3) + (1/4) = (3/7) |
| Subtraction | (a/b) - (c/d) = (a-c / b-d) | (5/6) - (2/1) = (3/5) |
| Scalar multiplication | k(a/b) = (ka/kb) | 3(2/4) = (6/12) |
| Magnitude | |(a/b)| = √(a² + b²) | |(3/4)| = √(9+16) = 5 |
| Parallel test | a = kb | (6/9) = 3(2/3) → parallel |