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IGCSE MATH: STATISTICS

STATISTICS LEARNER SUCCESS NOTES

Cambridge IGCSE Mathematics (0580)


TABLE OF CONTENTS

  • 1. Measures of Central Tendency (Mean, Median, Mode)
  • 2. Measures of Spread (Range, Interquartile Range)
  • 3. Scatter Diagrams and Correlation
  • 4. Line of Best Fit
  • 5. Stem-and-Leaf Diagrams
  • 6. Frequency Tables and Grouped Data
  • 7. Cumulative Frequency Diagrams
  • 8. Histograms and Frequency Density
  • 9. Pie Charts and Sector Angles
  • 10. Box-and-Whisker Plots
  • 11. Probability from Data

1. MEASURES OF CENTRAL TENDENCY

MEAN (Average)

Definition: Sum of all values divided by the number of values.

Formula: Mean = Σx ÷ n   |   Mean (frequency) = Σ(f·x) ÷ Σf   |   Mean (grouped) = Σ(f × midpoint) ÷ Σf

Example 1: 7, 9, 20, 3, 9

Mean = (7+9+20+3+9) ÷ 5 = 48 ÷ 5 = 9.6

Example 2 (frequency table):

Number of pets0123456
Frequency1235733
Mean = (0×1 + 1×2 + 2×3 + 3×5 + 4×7 + 5×3 + 6×3) ÷ 24 = 84 ÷ 24 = 3.5 pets

Example 3 (grouped data):

Height (h cm)2 < h ≤ 66 < h ≤ 1010 < h ≤ 1313 < h ≤ 17
Frequency23474538
Midpoints: 4, 8, 11.5, 15
Σ(f×mid) = 23×4 + 47×8 + 45×11.5 + 38×15 = 1555.5
Σf = 153 → Mean = 1555.5 ÷ 153 ≈ 10.2 cm

MEDIAN (Middle Value)

Definition: The middle value when data is arranged in order.

Position: (n+1)÷2 th value.

Example 1: 7,9,20,3,9 → order: 3,7,9,9,20 → median = 9
Example 2: 0.3,0.4,1.2,0.8,1.1,2.1 → order: 0.3,0.4,0.8,1.1,1.2,2.1 → median = (0.8+1.1)/2 = 0.95 kg

MODE (Most Common)

Definition: The value that appears most frequently.

Example: 7,9,20,3,9 → mode = 9 (twice)

Modal class: class with highest frequency (grouped data).

When to use each measure

  • Mean: No extreme outliers; all values used; numerical & fairly symmetric.
  • Median: Outliers present; skewed data; middle typical value.
  • Mode: Categorical data; most common item; discrete.

2. MEASURES OF SPREAD

RANGE

Range = Highest value – Lowest value
Data: 7,9,20,3,9 → range = 20–3 = 17

INTERQUARTILE RANGE (IQR)

IQR = Q3 – Q1

Quartile positions: Q1 = ¼(n+1)th, Q3 = ¾(n+1)th (or from cumulative frequency: n/4 and 3n/4).

Example (n=16): Q1 = 4th value, Q3 = 12th value; IQR = Q3–Q1

3. SCATTER DIAGRAMS AND CORRELATION

Types: Positive (upward), Negative (downward), Zero/No correlation, Strong/Weak.

Drawing: Crosses (×), label axes, do NOT join points.


4. LINE OF BEST FIT

Straight line through scatter: equal points above/below, passes through mean point.

Prediction: Interpolation (within data) – reliable; Extrapolation (outside) – less reliable.


5. STEM-AND-LEAF DIAGRAMS

Shows individual values, shape, median, mode. Key is essential.

Masses (kg): 0.3,0.4,1.2,0.8,1.1,2.1,1.7,1.8,1.2,2.3,0.7,1.1
 0 | 3 4 7 8
 1 | 1 1 2 2 7 8
 2 | 1 3
Key: 0|3 = 0.3 kg

Median: 12 values → between 6th & 7th = (1.1+1.2)/2 = 1.15 kg
Mode: 1.1 & 1.2 (bimodal)

Back-to-back stem-and-leaf

Girls          |     | Boys
            3 1| 15  | 8 9
        6 5 3 2| 20  | 3 5 6 9
    9 8 6 3 0  | 25  | 0 2 3 8
Key: 2|20|3 = 22 min (girls), 23 min (boys)

6. FREQUENCY TABLES AND GROUPED DATA

Class width = upper boundary – lower boundary
Midpoint = (lower + upper) ÷ 2
Modal class = class with highest frequency

Finding median class: total n ÷ 2, add frequencies until surpass position.


7. CUMULATIVE FREQUENCY DIAGRAMS

Running total; plot upper boundaries; join with smooth curve.

Height (h cm)h ≤ 6h ≤ 10h ≤ 13h ≤ 17h ≤ 20
Cumulative freq2370115153185

Reading: median = n/2, Q1 = n/4, Q3 = 3n/4, percentiles = (p/100)×total.

Example: total = 200 → 30th percentile position = 0.30×200 = 60 → read value from axis.

8. HISTOGRAMS AND FREQUENCY DENSITY

Frequency Density = Frequency ÷ Class Width

Bars touch; area = frequency.

Mass (m grams)496 < m ≤ 500500 < m ≤ 504504 < m ≤ 508508 < m ≤ 510
Frequency16741046
Class width4442
Freq density418.5263

9. PIE CHARTS AND SECTOR ANGLES

Sector angle = (frequency ÷ total) × 360°
FlavourVanillaStrawberryChocolateMango
Sold6897
Angle72°96°108°84°

Check total = 360°; reverse: frequency = (angle/360°) × total.


10. BOX-AND-WHISKER PLOTS

Five-number summary: Min, Q1, Median, Q3, Max.

|----[======|======]----|
↑    ↑      ↑      ↑    ↑
Min  Q1    Med    Q3   Max

IQR = Q3–Q1; median line inside box; whiskers to min/max.

Interpretation: symmetry, spread, compare medians and IQRs.


11. PROBABILITY FROM DATA

P(event) = frequency of event ÷ total frequency
Eggs: total 300, Very large = 81 → P = 81/300 = 27/100 = 0.27

From cumulative frequency: P(X > k) = (total – CF at k) / total.


QUICK REFERENCE FORMULAS

MeasureFormula
Mean (raw)Σx ÷ n
Mean (frequency)Σ(f·x) ÷ Σf
Mean (grouped)Σ(f·midpoint) ÷ Σf
Median position(n+1)/2 th value
RangeMax – Min
IQRQ3 – Q1
Q1 positionn/4 (CF diagram)
Q3 position3n/4 (CF diagram)
Class widthUpper – lower boundary
Midpoint(lower+upper)/2
Frequency densityFrequency ÷ class width
Sector angle(freq/total) × 360°
nth percentile (CF)position = (n/100)×total
Probabilityfavorable / total

EXAM TECHNIQUES AND COMMON ERRORS

General tips

  • Show all working – method marks.
  • Use appropriate accuracy (2–3 sf), include units.
  • Check if answer makes sense.

Common errors

  • Grouped mean: use midpoint, not boundaries.
  • Median: order data first; even n = average of two middles.
  • Cumulative frequency: plot at upper boundaries; smooth curve.
  • Histogram: freq density when unequal widths; bars touch.
  • Pie chart: angles sum to 360°.
  • Scatter: do not join points; line of best fit balanced.
  • Stem-and-leaf: ordered leaves; include key.

PRACTICE QUESTIONS WITH SOLUTIONS

Question 1: Mean and Median

Data: 7, 9, 20, 3, 9

(a) Mean = 48/5 = 9.6
(b) Median = 9
(c) Remove 9 (median stays 9, range 20-3=17)

Question 2: Grouped Data Mean

Height (h cm)2 < h ≤ 66 < h ≤ 1010 < h ≤ 1313 < h ≤ 17
Frequency23474538
Midpoints: 4,8,11.5,15
Σ(f×mid)=1555.5, Σf=153 → mean ≈ 10.2 cm

Question 3: Pie Chart

Walk:12, Car:7, Bicycle:9, Bus:4 → total 32. Walk angle = (12/32)×360° = 135°.

Question 4: Cumulative Frequency

n=80, median=35, Q1=25, Q3=45 → IQR=20. CF at 48 =72 → >48 = 8 students.

Question 5: Frequency Density

Mass (g)0<m≤0.50.5<m≤1.51.5<m≤3
Freq20189
Class widths: 0.5, 1, 1.5 → Freq density: 40, 18, 6

Question 6: Scatter & line of best fit

Positive correlation; at 5.5h → estimate ≈ 38 marks.

Question 7: Stem-and-leaf

 0 | 3 4 7 8
 1 | 1 1 2 2 7 8
 2 | 1 3
Key: 1|2 = 1.2 kg → median = 1.15 kg

FINAL CHECKLIST FOR EXAM SUCCESS

  • ✓ Know all formulas by heart
  • ✓ Practise all diagram types: scatter, stem, box, CF, histogram, pie
  • ✓ Show working – method marks
  • ✓ Use ruler for straight lines, protractor for pie
  • ✓ Label axes, include keys, check angles sum to 360°
  • ✓ Read questions twice – underline command words
  • ✓ Manage time: easy questions first

Good luck with your Statistics exam! 📊📈


End of Statistics Learner Success Notes

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